# STAT 3001 Week 4 Project Assignment

August 31, 2017

Question
Week 4 Project – STAT 3001

Student Name:

Date:

Instructions: To complete this project, you will need the following materials:

· STAT DISK User Manual (found in the classroom in Doc Sharing)

Part I. Analyze Data

Instructions

1. Open the filePassive and Active Smoke using menu optionDatasetsand thenElementary Stats, 11th Edition. This file contains some information on the continine levels in smokers, nonsmokers exposed to smoke (ETS), and nonsmokers not exposed to smoke (No ETS). How many observations are there in this file?

There are 40 samples with 3 different observations made on each sample for a total of 120 different observations.

2. What would you expect to find relative to the continine level in the groups?

The NOETS group lists the cotinine levels for subjects who are nonsmokers and have no exposure to

environmental tobacco smoke at home or work.

The ETS group lists cotinine levels for subjects who are nonsmokers exposed to tobacco smoke at

home or work.

The SMOKERS group lists cotinine levels for subjects who report tobacco use.

Serum cotinine is a metabolite of nicotine, meaning that cotinine is produced when nicotine is absorbed by the body. Higher levels of cotinine correspond to higher levels of exposure to smoke that contains nicotine.

Part II. Descriptive Statistics

3-6 Generate descriptive statistics for No ETS, Smokers and ETS groups and complete the following table. Round mean and standard deviation to 3 decimal places.

Variable

Sample

Mean

Sample

Standard Deviation

Sample Size

No ETS

16.35

62.534

40

Smokers

172.475

119.498

40

ETS

60.575

138.084

40

7. Did you get the results you expected here? Explain why.

8. Which of the three groups experienced the MOST variation? How do you know?

ETS – the variable in stat disk is the highest at 19067.17

Part III. Confidence Intervals

9. Generate a 90% interval for the mean of the No ETS group. Paste your results here.

Margin of error, E = 16.65918

90% Confident the population mean is within the range:

-0.3091758 < mean <33.00918

10. Generate a 90% interval for the mean of the Smoker group. Paste your results here.

Margin of error, E = 31.83449

90% Confident the population mean is within the range:

140.6405 < mean <204.3095

11. Generate a 90% interval for the mean of the ETS group. Paste your results here

Margin of error, E = 36.78584

90% Confident the population mean is within the range:

23.78916 < mean <97.36084

12. Create a graph below by illustrating all three confidence intervals on one graph using the tools in your word processor (example below). Stat Disk cannot do this for you.Create yourgraph and turn the font red. For this process, I just used the dashes and wrote a scale below the axes.

Here is an example, but it is not based on the data you are analyzing:

Case 1 14———————42

Case 2 35————————-70

________________________________________

0 20 40 60

13. Based on the confidence intervals shown above, what conclusion can you draw about whether the exposure to smoke leads to higher continine levels? Why?

Yes the exposure to smoke leads to higher continine levels. Due to the fact that ETS range 23.78916 < mean <97.36084 and No ETS range -0.3091758 < mean <33.00918

Part IV. Hypothesis Testing

14. Your researcher’s claim is that the continine level for the ETS group is not equal to zero. Compose a hypothesis test with a level of significance of .05 to test your claim.

Step 1. Determine parameter of interest and compose null and alternative hypotheses.

Step 2. Determine the sample mean, sample standard deviation, and sample size. [Hint: You recorded these previously in Part II, #3-6]

Step 3. Determine the likelihood that the population mean is actually not equal to 0 by completing aHypothesis Test: One Mean in STAT DISK. Use significance of0.05. Remember to change the pulldown option in Stat Disk to agree with the alternate hypothesis. Paste your results here.

Step 4. State your conclusion.Your conclusion statement should include the p-value and level of significance to phrase your conclusion.

15. For your second hypothesis test, your researcher’s claim is that the continine level in the NO ETS group is greater than zero. Perform a hypothesis test using a significance level of .01 to test your claim.

Step 1. Determine parameter of interest and compose null and alternative hypotheses.

Step 2. Determine the sample mean, sample standard deviation, and sample size. [Hint: You recorded these previously in Part II, #3-6]

Step 3. Determine the likelihood that the population mean is actually greater than 0 by completing aHypothesis Test: One Mean in STAT DISK. Use significance of0.01. Remember to change the pulldown option in Stat Disk to agree with the alternate hypothesis. Paste results here.

Step 4. State your conclusion.Your conclusion statement should include the p-value and level of significance to phrase your conclusion.

16. Answer the following questions based on the above hypothesis test.

a. What is the p-value for the hypothesis test in #15 and what does it represent? (Look at page 383 in the text)

b. Given that your data, hypotheses, and p-value do not change,what would need to be different in order for you to REJECT the null hypothesis? (What do you compare to make your rejection decision?)

Submit your final draft of your Word file by going to Week 4, Project, and follow the directions under Week 4 Assignment 2. Please use the naming convention "WK4Assgn2+first initial+last name" as the Submission Title.

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