How do you find the derivative for ##f(x)=sinxcosx##?

| May 27, 2018

You can use the :
if: ##k(x)=f(x)g(x)##
##k'(x)=f'(x)g(x)+f(x)g'(x)##
In your case:
##f'(x)=cos(x)cos(x)+sin(x)(-sin(x))=##
##=cos^2(x)-sin^2(x)=cos(2x)##

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