Ashworth stat exam help

| August 30, 2017

Question
Question 1 of 40

2.5 Points

z = 1.8 for Ha: µ > claimed value. What is the P-value for the test? ?

A. 0.9641

B. 3.59

C. 96.41

D. 0.0359

2.

Question 2 of 40

2.5 Points

A consumer advocacy group claims that the mean amount of juice in a 16

ounce bottled drink is not 16 ounces, as stated by the bottler.

Determine the null and alternative hypotheses for the test described.

A.

H0: µ = 16 ounces Ha: µ 16 ounces

D.

H0: µ = 16 ounces Ha: µ ¹ 16 ounces

3. A long-distance telephone company claims that the mean duration of long-distance telephone calls originating in one town was greater than 9.4 minutes, which is the average for the state. Determine the conclusion of the hypothesis test assuming that the results of the sampling do not lead to rejection of the null hypothesis.

A. Conclusion: Support the claim that the mean is less than 9.4 minutes.

B. Conclusion: Support the claim that the mean is greater than 9.4 minutes.

C. Conclusion: Support the claim that the mean is equal to 9.4 minutes.

D. Conclusion: Do not support the claim that the mean is greater than 9.4 minutes

4. The owner of a football team claims that the average attendance at home games is over 4000, and he is therefore justified in moving the team to a city with a larger stadium. Assume that a hypothesis test of the claim has been conducted and that the conclusion of the test was to reject the null hypothesis. Identify the population to which the results of the test apply.

A. All games played by the team in question in which the attendance is over 4000

B. All future home games to be played by the team in question

C. All home games played by the team in question

D. None of the populations given are appropriate

Question 5 of 40

2.5 Points

In 1990, the average duration of long-distance telephone calls originating in one town was 9.3 minutes. A long-distance telephone company wants to perform a hypothesis test to determine whether the average duration of long-distance phone calls has changed from the 1990 mean of 9.3 minutes. Formulate the null and alternative hypotheses for the study described.

A.

Ho: µ = 9.3 minutes H a : µ 9.3 minutes

C.

Ho: µ = 9.3 minutes H a : µ ¹ 9.3 minutes

D.

Ho: µ ¹ 9.3 minutes H a : µ = 9.3 minutes

Question 6 of 40

2.5 Points

In the past, the mean running time for a certain type of flashlight battery has been 9.8 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has increased as a result. The hypotheses are:

H0 : µ = 9.8 hours

Ha : µ > 9.8 hours

Suppose that the results of the sampling lead to rejection of the null hypothesis. Classify that conclusion as a Type I error, a Type II error, or a correct decision, if in fact the mean running time has not increased.

A. Type I error

B. Type II error

C. Correct decision

D. Can not be determined from this information

Question 7 of 40

2.5 Points

A supplier of DVDs claims that no more than 1% of the DVDs are defective. In a random sample of 600 DVDs, it is found that 3% are defective, but the supplier claims that this is only a sample fluctuation. At the 0.01 level of significance, test the supplier’s claim that no more than 1% are defective.

A. Do not reject the null hypothesis and conclude that there is evidence to support the claim that more than 1% of the DVDs are defective.

B. Reject the null hypothesis and conclude that there is insufficient evidence to support the claim that more than 1% of the DVDs are defective.

C. Do not reject the null hypothesis and conclude that there is insufficient evidence to support the claim that more than 1% of the DVDs are defective.

D. Reject the null hypothesis and conclude that there is sufficient evidence to support the claim that more than 1% of the DVDs are defective.

Question 8 of 40

2.5 Points

A consumer group claims that the mean running time for a certain type of flashlight battery is not the same as the manufacturer’s claims. Determine the null and alternative hypotheses for the test described.

A.

H0: µ = Manufacturer’s claims Ha: µ Manufacturer’s claims

D.

H0: µ ¹ Manufacturer’s claims Ha: µ = Manufacturer’s claims

Question 9 of 40

2.5 Points

A two-tailed test is conducted at the 5% significance level. What is the left tail percentile required to reject the null hypothesis?

A. 97.5%

B. 5%

C. 2.5%

D. 95%

Question 10 of 40

2.5 Points

A poll of 1,068 adult Americans reveals that 52% of the voters surveyed prefer the Democratic candidate for the presidency. At the 0.05 significance level, test the claim that more than half of all voters prefer the Democrat.

A. Reject the null hypothesis. Conclude that there is insufficient evidence that more than half of all voters prefer Democrats.

B. Do not reject the null hypothesis. Conclude that there is sufficient evidence that more than half of all voters prefer Democrats.

C. Reject the null hypothesis. Conclude that there is sufficient evidence that more than half of all voters prefer Democrats.

D. Do not reject the null hypothesis. Conclude that there is insufficient evidence that more than half of all voters prefer Democrats.

Question#11

A researcher claims that the amounts of acetaminophen in a certain brand of cold tablets have a mean different from the 600 mg claimed by the manufacturer. Test this claim at the 0.02 level of significance. The mean acetaminophen content for a random sample of n = 41 tablets is 603.3 mg. Assume that the population standard deviation is 4.9 mg.

A. Since the test statistic is greater than the critical z, there is sufficient evidence to accept the null hypothesis and to support the claim that the mean content of acetaminophen is 600 mg.

B. Since the test statistic is greater than the critical z, there is sufficient evidence to reject the null hypothesis and to support the claim that the mean content of acetaminophen is not 600 mg.

C. Since the test statistic is less than the critical z, there is sufficient evidence to reject the null hypothesis and to support the claim that the mean content of acetaminophen is not 600 mg.

D. Since the test statistic is greater than the critical z, there is insufficient evidence to reject the null hypothesis and to support the claim that the mean content of acetaminophen is not 600

Question 12 of 40

2.5 Points

A skeptical paranormal researcher claims that the proportion of Americans that have seen a UFO is less than 1 in every one thousand. State the null hypothesis and the alternative hypothesis for a test of significance.

A.

H0: p = 0.001 Ha: p > 0.001

B.

H0: p = 0.001 Ha: p 0.001 Ha: p = 0.001

D.

H0: p months. Assume that the population standard deviation is 7 months. Test the null hypothesis that µ = 18.7 at the 0.05 significance level.

A.

Do not reject the null hypothesis and conclude that the claim that the mean is different from 18.7 months is supported.

B.

Do not reject the null hypothesis and conclude that the claim that the mean is different from 18.7 months cannot be supported.

C.

Reject the null hypothesis and conclude that the claim that the mean is different from 18.7 months is supported.

D.

Reject the null hypothesis and conclude that the claim that the mean is different from 18.7 months cannot be supported.

Question 14 of 40

2.5 Points

In the past, the mean running time for a certain type of flashlight battery has been 8.0 hours. The manufacturer has introduced a change in the production method and wants to perform a hypothesis test to determine whether the mean running time has increased as a result. The hypotheses are:

H0 : µ = 8.0 hours

Ha : µ > 8.0 hours

Explain the meaning of a Type II error.

A. Concluding that µ > 8.0 hours when in fact µ > 8.0 hours

B. Failing to reject the hypothesis that µ = 8.0 hours when in fact µ >
8.0 hours

C. Concluding that µ > 8.0 hours

D. Failing to reject the hypothesis that µ = 8.0 hours when in fact µ = 8.0 hours

Question 15 of 40

2.5 Points

A two-tailed test is conducted at the 5% significance level. What is the P-value required to reject the null hypothesis?

A. Greater than or equal to 0.10

B. Less than or equal to 0.05

C. Less than or equal to 0.10

D. Greater than or equal to 0.05

Question 16 of 40

2.5 Points

.jpg” alt=”https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%207%20exam/MA260%20Lesson%207%20exam%20question%2022.JPG”>

without computing a P-value, determine whether the alternate hypothesis is supported and give a reason for your conclusion.

A.

.jpg” alt=”https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%207%20exam/MA260%20Lesson%207%20exam%20question%2022%20_A_.JPG”>is less than 1 standard deviation above the claimed mean.

B.

.jpg” alt=”https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%207%20exam/MA260%20Lesson%207%20exam%20question%2022%20_A_.JPG”>is more than 4 standard deviations above the claimed mean.

C.

.jpg” alt=”https://study.ashworthcollege.edu/access/content/group/8ef8b2f7-197d-41de-a4c4-db81a717c013/v9/Images/Lesson%207%20exam/MA260%20Lesson%207%20exam%20question%2022%20_C_.JPG”>is less than 1 standard deviation above the claimed mean.

D.

Question 17 of 40

2.5 Points

A right-tailed test is conducted at the 5% significance level. Which of the following z-scores is the smallest one in absolute value that leads to rejection of the null hypothesis? ?

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