6. Use the correct bivariate statistical test

| September 12, 2019

6. Use the correct bivariate statistical test to examine the relationship between the Instit_Confid index (the index you created in question 3) and the variable called class (subjective class identification). What test did you run? In the space provided below, describe the results and interpret the outcome of the test (10 points). Be sure to insert the output from the SPSS procedure below. Descriptives Instit_Confid Summated Index Using the Newly 12 Variable 95% Confidence Interval for Mean N Mean Std. Deviation Std. Error Lower Bound Upper Bound Minimu 1 LOWER CLASS 124 22.8871 4.38069 .39340 22.1084 23.6658 12 2 WORKING CLASS 687 23.1456 3.96880 .15142 22.8483 23.4429 12 3 MIDDLE CLASS 628 23.9411 4.01807 .16034 23.6262 24.2559 12 4 UPPER CLASS 40 24.9000 3.31121 .52355 23.8410 25.9590 15 1479 23.5091 4.03382 .10489 23.3034 23.7149 12 Total ANOVA Instit_Confid Summated Index Using the Newly 12 Variable Sum of Squares Between Groups df Mean Square 333.343 3 111.114 Within Groups 23716.283 1475 16.079 Total 24049.627 1478 F Sig. 6.911 .000 Multiple Comparisons Dependent Variable: Instit_Confid Summated Index Using the Newly 12 Variable LSD (I) class SUBJECTIVE CLASS (J) class SUBJECTIVE IDENTIFICATION CLASS IDENTIFICATION 1 LOWER CLASS 2 WORKING CLASS 2 WORKING CLASS 3 MIDDLE CLASS Mean Difference (I-J) 95% Confidence I Std. Error Sig. Lower Bound -.25846 .39124 .509 -1.0259 3 MIDDLE CLASS -1.05399* .39404 .008 -1.8269 4 UPPER CLASS -2.01290* .72914 .006 -3.4432 1 LOWER CLASS .25846 .39124 .509 -.5090 3 MIDDLE CLASS -.79552* .22138 .000 -1.2298 4 UPPER CLASS -1.75444* .65221 .007 -3.0338 1 LOWER CLASS 1.05399* .39404 .008 .2810 .79552* .22138 .000 .3613 2 WORKING CLASS Up 4 UPPER CLASS 4 UPPER CLASS -.95892 .65389 .143 -2.2416 1 LOWER CLASS 2.01290* .72914 .006 .5826 2 WORKING CLASS 1.75444* .65221 .007 .4751 .95892 .65389 .143 -.3237 3 MIDDLE CLASS *. The mean difference is significant at the 0.05 level. 7. Use the correct bivariate statistical test to examine the relationship between the Instit_Confid and the sex (i.e., gender) variable. What test did you run? In the space provided below, describe the results and interpret the outcome of the test (10 points). Be sure to insert the output from the SPSS procedure below. Group Statistics sex RESPONDENTS SEX N Mean Std. Deviation Std. Error Mean Instit_Confid Summated 1 MALE 684 23.4854 4.00308 .15306 Index Using the Newly 12 2 FEMALE 803 23.4969 4.07363 .14376 Variable Independent Samples Test Levene’s Test for Equality of Variances t-test for Equality of Means Mean Sig. (2F Instit_Confid Equal variances .723 Sig. .395 t df tailed) Std. 95% Confidence Error Interval of the Differenc Differenc e e Difference Lower Upper -.055 1485 .956 -.01151 .21028 -.42398 .40097 -.055 1455. .956 -.01151 .20998 -.42341 .40040 Summated Index assumed Using the Newly Equal variances 12 Variable not assumed 143 8.Use the correct bivariate statistical test to examine the relationship between the Instit_Confid index and the variable called age (Age of Respondent). What test did you run? In the space provided below, describe the results and interpret the outcome of the test (10 points). Be sure to insert the output from the SPSS procedure below. Descriptive Statistics Mean age AGE OF Std. Deviation N 49.01 17.412 2529 23.4916 4.03998 1487 RESPONDENT Instit_Confid Summated Index Using the Newly 12 Variable Correlations Instit_Confid Summated Index Using the age AGE OF Pearson Correlation RESPONDENT Sig. (2-tailed) Sum of Squares and Cross- age AGE OF Newly 12 RESPONDENT Variable 1 -.058* .026 766421.595 -5938.754 303.173 -4.013 2529 1481 -.058* 1 products Covariance N Instit_Confid Summated Pearson Correlation Index Using the Newly 12 Sig. (2-tailed) Variable Sum of Squares and Cross- .026 -5938.754 24253.645 -4.013 16.321 1481 1487 products Covariance N *. Correlation is significant at the 0.05 level (2-tailed). 9. Use the correct bivariate statistical test to examine the relationship between the Instit_Confid index and the variable called age (Age of Respondent) while controlling for sex (i.e., gender). What test did you run? In the space provided below, describe the results and interpret the outcome of the test (10 points). Be sure to insert the output from the SPSS procedure below. Descriptive Statistics Mean Instit_Confid Summated Std. Deviation N 23.4970 4.03868 1481 48.8325 17.12116 1481 1.5388 .49866 1481 Index Using the Newly 12 Variable age AGE OF RESPONDENT sex RESPONDENTS SEX Correlations Instit_Confid Summated Index Control Variables -none-a Instit_Confid Summated Index Correlation Using the Newly 12 Variable age AGE OF RESPONDENT sex RESPONDENTS SEX sex RESPONDENTS SEX age AGE OF RESPONDENT a. Cells contain zero-order (Pearson) correlations. age AGE OF RE 12 Variable RESPONDENT 1.000 -.058 Significance (2-tailed) . .026 df 0 1479 -.058 1.000 Significance (2-tailed) .026 . df 1479 0 Correlation .000 .020 Significance (2-tailed) .996 .447 df 1479 1479 1.000 -.058 Significance (2-tailed) . .026 df 0 1478 -.058 1.000 Significance (2-tailed) .026 . df 1478 0 Correlation Instit_Confid Summated Index Correlation Using the Newly 12 Variable Using the Newly Correlation 10. Use the correct bivariate statistical test to examine the relationship between the Instit_Confid_Quartiles (the variable you created in question 4) and the variable fund (how fundamentalist is respondent currently). What test did you run? In the space provided below, describe the results and interpret the outcome of the test (10 points). Be sure to insert the output from the SPSS procedure below. Case Processing Summary Cases Valid N Instit_Confid_Quartiles 1430 Missing Percent 56.3% N Total Percent 1108 43.7% N Percent 2538 100.0% Recode variable into quartiles * fund HOW FUNDAMENTALIST IS R CURRENTLY Instit_Confid_Quartiles Recode variable into quartiles * fund HOW FUNDAMENTALIST IS R CURRENT fund HOW FUNDAMENTALIST IS R CU 1 FUNDAMENTALI ST Instit_Confid_Quartiles Recode 1.00 25% Quartile Count variable into quartiles Expected Count % within fund HOW 2 MODERATE 108 187 102.0 185.9 32.0% 30.5% 74 120 73.3 133.5 22.0% 19.5% 86 150 88.1 160.6 25.5% 24.4% 69 157 73.5 134.0 FUNDAMENTALIST IS R CURRENTLY 2.00 50% Quartile Count Expected Count % within fund HOW FUNDAMENTALIST IS R CURRENTLY 3.00 75% Quartile Count Expected Count % within fund HOW FUNDAMENTALIST IS R CURRENTLY 4.00 100% Quartile Count Expected Count 3 % within fund HOW 20.5% 25.6% 337 614 337.0 614.0 100.0% 100.0% FUNDAMENTALIST IS R CURRENTLY Total Count Expected Count % within fund HOW FUNDAMENTALIST IS R CURRENTLY Chi-Square Tests Asymptotic Significance (2Value df sided) 13.213a 6 .040 13.184 6 .040 Linear-by-Linear Association .000 1 .997 N of Valid Cases 1430 Pearson Chi-Square Likelihood Ratio a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 73.29. Symmetric Measures Asymptotic Value Ordinal by Ordinal Approximate Standard Errora Approximate Tb Significance Kendall’s tau-b -.001 .022 -.055 .956 Kendall’s tau-c -.001 .023 -.055 .956 Gamma -.002 .032 -.055 .956 N of Valid Cases 1430 a. Not assuming the null hypothesis. b. Using the asymptotic standard error assuming the null hypothesis. …
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